3^2(x-1)-8(3^x-2)=1

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Solution for 3^2(x-1)-8(3^x-2)=1 equation: 



3^2(x-1)-8(3^x-2)=1

We move all terms to the left:

3^2(x-1)-8(3^x-2)-(1)=0

We multiply parentheses

3^2(x-1)-24x+16-1=0

We add all the numbers together, and all the variables

-24x+3^2(x-1)+15=0

We move all terms containing x to the left, all other terms to the right

-24x+3^2(x-1)=-15

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